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28 由图2所示有限单元的节点构造以及节点自由度：、、、、、、、、和( i =1,2,3; j =1,2,3,4),节点自由度向量：
[29]
29 (A.1)
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30 三个节点构成的单元自由度向量：
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31 (A.2)
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32 基于拉格朗日插值基可构造基本未知量、、、、和的拉格朗日插值函数：
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33 (A.3)
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34 其中,形函数向量、、、、和定义为：
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35 (A.4)
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36 式(A.4)中,为13阶单位矩阵,而插值基定义如下：
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37 (A.5)
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38 利用式(1)和式(2)可导出：
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39 (A.6)
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40 其中：
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44 根据式(3)可以继续导出应变插值函数：
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45 (A.7)
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46 其中：
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